Solve Word Problem: Becky Had 216 Stamps

  • Thread starter Taylor_1989
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In summary, Becky had 216 stamps, the thing is she is not to sure how to set up the equation and show her working below.
  • #1
Taylor_1989
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I got the word problem off the internet, just for a bit of practice, and get slightly lost towards the end. It tells me becky had 216 stamps, the thing is I am not to sure how to set up the equation I will show my working below.


Ada, Becky and Cathy had some stamps. Cathy had 20%more stamps than Ada. Cathy had 75% as many stamps as Becky. Becky gave 45 stamps to Ada and Cathy in the ratio of 4:1 so that all three girls will have the same number of stamps.

a) How many stamps did Becky have at first?

1. [itex]C=A*120\%[/itex] [itex]C=B*75\%[/itex]

2. ratio [itex]\frac{45}{5}=9[/itex] [itex]9*4=36[/itex][itex]9*1=9[/itex]

3. [itex]B-45=C+9=A+36[/itex]

This is the point of confusion, I am not quite sure how to solve for B. I know I should some how sub 1 into 3 to make the equation, but not to sure how? could someone point me in the right direction, to how to solve this.

I did convert the percentages to fraction: [itex]\frac{6}{5}[/itex] and [itex]\frac{3}{4}[/itex] but still did not help.

Would really apprecaite the guidence
 
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  • #2
From this point, all you need to do is substitute [itex] .75B [/itex] for [itex]C[/itex] and solve for [itex]B[/itex], forgetting about [itex]A[/itex], though you can check to make sure you got it right by solving for all of the final stamp counts.
 
  • #3
bossman27 said:
From this point, all you need to do is substitute [itex] .75B [/itex] for [itex]C[/itex] and solve for [itex]B[/itex], forgetting about [itex]A[/itex], though you can check to make sure you got it right by solving for all of the final stamp counts.

If I solve for [itex] B [/itex] I get [itex] 207 [/itex], I should be getting [itex]216[/itex]

Here is how I did it, I personally can't see where I am going wrong, but obviously I am somewhere: [itex]B-45=\frac{3}{4}B+9[/itex] [itex]\rightarrow[/itex] [itex]4(B-45)=3(B+9)[/itex] [itex]\rightarrow[/itex] [itex]4B-180=3B+27[/itex] [itex]\rightarrow[/itex] [itex]B=207[/itex]
 
  • #4
[itex] B - 45 = .75B + 9 [/itex]

[itex] .25B = 54 \Rightarrow B = 216 [/itex]

Your problem was that you solved it as though it was:

[itex] B - 45 = \frac{3}{4}(B+9) [/itex]

and [itex] \frac{3}{4}(B+9) \neq \frac{3}{4} B + 9 [/itex]
 
  • #5
Got it, thanks for that fella; been bugging me all day.
 

1. How many stamps did Becky start with?

Becky started with 216 stamps.

2. How many stamps did Becky have left after using 100 stamps?

Becky would have 116 stamps left after using 100 stamps.

3. If Becky gave away 50 stamps, how many stamps would she have left?

Becky would have 166 stamps left after giving away 50 stamps.

4. How many stamps did Becky have to begin with if she now has 300 stamps?

Becky must have started with 84 stamps if she now has 300 stamps.

5. If Becky bought 50 more stamps, how many stamps would she have in total?

Becky would have 266 stamps in total after buying 50 more stamps.

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