- #1
Taylor_1989
- 402
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I got the word problem off the internet, just for a bit of practice, and get slightly lost towards the end. It tells me becky had 216 stamps, the thing is I am not to sure how to set up the equation I will show my working below.
Ada, Becky and Cathy had some stamps. Cathy had 20%more stamps than Ada. Cathy had 75% as many stamps as Becky. Becky gave 45 stamps to Ada and Cathy in the ratio of 4:1 so that all three girls will have the same number of stamps.
a) How many stamps did Becky have at first?
1. [itex]C=A*120\%[/itex] [itex]C=B*75\%[/itex]
2. ratio [itex]\frac{45}{5}=9[/itex] [itex]9*4=36[/itex][itex]9*1=9[/itex]
3. [itex]B-45=C+9=A+36[/itex]
This is the point of confusion, I am not quite sure how to solve for B. I know I should some how sub 1 into 3 to make the equation, but not to sure how? could someone point me in the right direction, to how to solve this.
I did convert the percentages to fraction: [itex]\frac{6}{5}[/itex] and [itex]\frac{3}{4}[/itex] but still did not help.
Would really apprecaite the guidence
Ada, Becky and Cathy had some stamps. Cathy had 20%more stamps than Ada. Cathy had 75% as many stamps as Becky. Becky gave 45 stamps to Ada and Cathy in the ratio of 4:1 so that all three girls will have the same number of stamps.
a) How many stamps did Becky have at first?
1. [itex]C=A*120\%[/itex] [itex]C=B*75\%[/itex]
2. ratio [itex]\frac{45}{5}=9[/itex] [itex]9*4=36[/itex][itex]9*1=9[/itex]
3. [itex]B-45=C+9=A+36[/itex]
This is the point of confusion, I am not quite sure how to solve for B. I know I should some how sub 1 into 3 to make the equation, but not to sure how? could someone point me in the right direction, to how to solve this.
I did convert the percentages to fraction: [itex]\frac{6}{5}[/itex] and [itex]\frac{3}{4}[/itex] but still did not help.
Would really apprecaite the guidence