We know that the standard deviation(adsbygoogle = window.adsbygoogle || []).push({}); _{[sig]}for a random walk, represented by a net distance d, to be approximately the square root of the total number of steps N, each of length L, from the origin. I. e., d~N^{1/2}L~_{[sig]}L.

Does the angle attained after these steps also have a significant standard deviation?

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# Standard deviation angle for random walk?

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