- #1
Bill Foster
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Homework Statement
Problem 1.2 from the book Introduction to Quantum Mechanics (2e) by Griffiths:
Suppose a rock is dropped off a cliff of height h. As it
falls, a million photos are snapped, at random intervals. On each picture the distance the rock has fallen is measured.
a) Find the standard deviation of the distribution.
The Attempt at a Solution
Starting with the equation of motion (assuming it falls in the positive x direction):
[tex]x(t)=x_0+v_0(t)+\frac{1}{2}at^2=\frac{1}{2}gt^2[/tex]
The time T it takes to fall:
[tex]h=\frac{1}{2}gt^2[/tex]
[tex]T=\sqrt{\frac{2h}{g}}[/tex]
Probability a picture is taken in interval dt:
[tex]\frac{dt}{T}=dt \sqrt{\frac{g}{2h}}=\frac{dx}{gt}\sqrt{\frac{g}{2h}}=\frac{1}{2h}\frac{1}{\sqrt{gt}}dx=\frac{1}{2\sqrt{hx}}dx[/tex]
So the probability density is:
[tex]\rho(x)=\frac{1}{2\sqrt{hx}}[/tex]
Expectation Value:
[tex]\mu=\int_0^h x \rho(x)dx=\int_0^h x \frac{1}{2\sqrt{hx}}dx=\frac{1}{2\sqrt{h}}\frac{2}{3}x^\frac{3}{2}=\frac{h}{3}[/tex]
Standard deviation:
[tex]\sigma^2=\int_0^h (x-\mu)^2 \rho(x)dx[/tex]
[tex]\sigma^2=\int_0^h (x-\frac{h}{3})^2 \frac{1}{2\sqrt{hx}}dx=\frac{4}{45}h^2[/tex]
[tex]\sigma=\frac{2h}{\sqrt{45}}[/tex]
Look right?