Standard entropy of formation ?

In summary: The burning of magnesium in excess oxygen can be represented by the following equation:2Mg + O2 → 2MgOFrom this, we can see that for every 2 moles of magnesium that react, 1 mole of oxygen is consumed and 2 moles of magnesium oxide are produced.A) To find the entropic energy change, we need to first find the number of moles of magnesium present in 25 grams of magnesium. Using the molar mass of magnesium (24.31 g/mol), we can calculate the number of moles as follows:25 g Mg x (1 mol Mg / 24.31 g Mg) = 1.03 mol MgSince we have 1.03
  • #1
explore88
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standard entropy of formation ??

Homework Statement



the standard entropy of formation of magnesium is 32.7 J/mol k , That of oxygen gases 205.2 J/mol k

at that magnesium oxide is 26.9 J/mol k .

A) What is the entropic energy change when 25 grams of magnesium are burned inexcess oxygen at 25 celsius ??

B) Does the burning of magnesium in oxygen lead to increase or decrease in entropy in the system ??

I hope the solution step by step ..

regards ^_^ ..

Homework Equations





The Attempt at a Solution

 
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  • #2


first find the no. of moles of Mg you have.
that would combine with the same no. of moles of O to give the same no. of moles of MgO.

entropy change = entropy of form of products - sum of entropy of form of reactants
 
  • #3


explore88 said:

Homework Statement



the standard entropy of formation of magnesium is 32.7 J/mol k , That of oxygen gases 205.2 J/mol k

at that magnesium oxide is 26.9 J/mol k .

A) What is the entropic energy change when 25 grams of magnesium are burned inexcess oxygen at 25 celsius ??

B) Does the burning of magnesium in oxygen lead to increase or decrease in entropy in the system ??

I hope the solution step by step ..

regards ^_^ ..

You should probably write down some reactions to help you visualize the problem.
 

What is the standard entropy of formation?

The standard entropy of formation is a thermodynamic property that measures the degree of disorder or randomness of a substance at standard conditions (25°C and 1 atm). It is denoted by the symbol ΔS° and is expressed in units of joules per mole per kelvin (J/mol·K).

How is the standard entropy of formation calculated?

The standard entropy of formation is calculated by subtracting the sum of the standard entropies of the reactants from the sum of the standard entropies of the products. This can be represented by the equation: ΔS° = ΣS°(products) - ΣS°(reactants).

What factors affect the standard entropy of formation?

The standard entropy of formation can be influenced by several factors, including temperature, pressure, molecular structure, and state of matter. Generally, substances with more complex molecular structures or higher molecular weights tend to have higher standard entropies of formation.

Why is the standard entropy of formation important?

The standard entropy of formation is an important thermodynamic property as it provides information about the stability and spontaneity of a chemical reaction. It also allows for the prediction of how a substance will behave under different conditions.

How is the standard entropy of formation used in chemistry?

The standard entropy of formation is used in various applications in chemistry, such as in the calculation of standard free energy of formation, determination of equilibrium constants, and prediction of reaction spontaneity. It is also used in the design and optimization of chemical processes and in the study of thermodynamic properties of substances.

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