- #1

- 83

- 0

y = x^2 + 8x + 20

I thought this was the standard form for parabolas?? I tried this as the answer but it said it was wrong

y = (x+4)^2 +4

Thanks for the help! :-)

- Thread starter quickclick330
- Start date

- #1

- 83

- 0

y = x^2 + 8x + 20

I thought this was the standard form for parabolas?? I tried this as the answer but it said it was wrong

y = (x+4)^2 +4

Thanks for the help! :-)

- #2

symbolipoint

Homework Helper

Education Advisor

Gold Member

- 5,999

- 1,094

- #3

- 83

- 0

y = x^2 +8x + 20 + 16 - 16

y = (x^2 + 8x +16) + 4

then factor...

y = (x + 4)^2 + 4

which is exactly what I got before???

- #4

symbolipoint

Homework Helper

Education Advisor

Gold Member

- 5,999

- 1,094

That appears to be correct. That IS the standard form for your equation given in your exercise. The parabola has been shifted upward by 4 units and to the left by 4 units from standard position.

y = x^2 +8x + 20 + 16 - 16

y = (x^2 + 8x +16) + 4

then factor...

y = (x + 4)^2 + 4

which is exactly what I got before???

- #5

- 83

- 0

- Replies
- 3

- Views
- 10K

- Last Post

- Replies
- 1

- Views
- 5K

- Last Post

- Replies
- 2

- Views
- 2K

- Replies
- 2

- Views
- 3K

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 2K

- Last Post

- Replies
- 3

- Views
- 9K

- Last Post

- Replies
- 5

- Views
- 988

- Last Post

- Replies
- 7

- Views
- 4K