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- Thread starter aisha
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The semi-major axis will be the root of the largests denominator

The semi-minor axis will be the root of the smallest denominator

The coordinates of the center will be (h,k) for and elispse in the form (just a simple translation)

[tex]\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}=1[/tex]

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how about the coordinates of the foci?

- #4

BobG

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Both focii lie on the major axis. For a horizontal ellipse, your coordinates have to be (x,0). For a vertical ellipse, (0,y).

The covertex is the point where the minor axis intersects the ellipse. Half of the minor axis is the semi-minor axis (b) and half of the major axis is the semi-major axis (a). The distance from either focus to the covertex is equal to the semi-major axis.

Now you know two sides of your triangle. You know the hypotenuse which happens to have a length equal to the semi-major axis (a). You know the semi-minor axis (b) which forms one leg of your triangle. You also know the minor axis is perpendicular to the major axis, so you know you have a right triangle.

You use the Pythagorean thereom to find the missing length: the length from your origin to the focus. The length will be equal to your

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lol woh bob u got way too complicated how did triangles get into this :rofl:

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BobG

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how do I open the attachment?

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