1. The problem statement, all variables and given/known data An Exceptional standing jump would raise a person 0.80m off the ground. To do this, what force must a 66Kg person exert against the ground? Assume the person crouches a distance of 0.20m prior to jumping, and thus the upward force has this distance to act over before he leaves the ground. 2. Relevant equations 3. The attempt at a solution Heres what i attempted. The upward force would be the normal force(Fn) which is the same as the Force of gravity so i caculated that and i got Fg=646.8 the force going down would be the applied force(Fa) Heres what i got fo far before i got stumped.. Fa-Fn=ma Fa-646.8=66a I dont know how i would get acceleration?