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Standing Transverse wave.

  1. Apr 26, 2004 #1
    The diagram represents a snapshot of a standing transverse wave on a flexible string taken when the displacement is at a maximum. The string is 1.34 m long with tension 6 N. The total mass of the string is 12.22 g. Find the period of the oscillation.

    The diagram is unlabeled. it just shows one and a half wavelengths.


    a loop up, a loop down, another loop up. is what it looks like.

    i dunno if that makes sense.. it's pretty simple i just don't know how else to show you the diagram.
     
  2. jcsd
  3. Apr 26, 2004 #2

    HallsofIvy

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    I think I understand what the diagram looks like. What I don't see is any question!
     
  4. Apr 26, 2004 #3
    Find the period of oscillation.
     
  5. Apr 26, 2004 #4

    Doc Al

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    Start by finding the speed of the wave. Hint: That speed depends on the tension, mass, and length of the string.
     
  6. Apr 26, 2004 #5
    I found that, but what can i do next?

    I have the length of the string, but i can't seem to find a way to find the wavelength, or the length of 1 1/2 wave lengths.
     
  7. Apr 27, 2004 #6

    Doc Al

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    According to your description, doesn't the length of the string equal 1 1/2 wavelengths?
     
  8. Apr 27, 2004 #7
    Maybe i should try that again, i just got confused on what length meant.
     
  9. Apr 27, 2004 #8
    Got it! thanks! hadn't tried that with my new velocity.

    Much appreciated.
     
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