Adjacent antinodes of a standing wave on a string are a distance 14.5 cm apart. A particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cm and period 8.00×10-2 s . The string lies along the + x - axis and is fixed at x = 0.(adsbygoogle = window.adsbygoogle || []).push({});

Find the displacement of a point on the string as a function of position and time.

Find the speed of propagation of a transverse wave in the string.

Find the amplitude at a point a distance 3.20 to the right of an antinode.

- the first question was pretty easy easy i just used the formula :

A*cos(2*pi*t/T)*sin(2*pi*x/(2*s)) T = period A = amplitude

and i got the result: 3.25*10^(-3)m. which is correct, now can anybody give me any clues on how to calculate the speed of the propagation and the amplitude at 3.20 to the right of the antinode?

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# Homework Help: Standing Wave Question?

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