Adjacent antinodes of a standing wave on a string are a distance 14.5 cm apart. A particle at an antinode oscillates in simple harmonic motion with amplitude 0.850 cm and period 8.00×10-2 s . The string lies along the + x - axis and is fixed at x = 0. Find the displacement of a point on the string as a function of position and time. Find the speed of propagation of a transverse wave in the string. Find the amplitude at a point a distance 3.20 to the right of an antinode. - the first question was pretty easy easy i just used the formula : A*cos(2*pi*t/T)*sin(2*pi*x/(2*s)) T = period A = amplitude and i got the result: 3.25*10^(-3)m. which is correct, now can anybody give me any clues on how to calculate the speed of the propagation and the amplitude at 3.20 to the right of the antinode?