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1. The problem statement, all variables and given/known data

see question 2a, b

2. Relevant equations

a) v=f(wavelength)

b) v= sqrt(F/(m/L))

3. The attempt at a solution

a) f=2.5 Hz, t=1.0 s and one wavelength on the graph is I guess 0.4 m?

v=2.5(.4)=1 m/s

b) f=5.0 Hz, tension same

v= sqrt(F/(m/L)) means that a change in frequency will not change the velocity?

1=5(wavelength)

wavelength= 0.2 m?

1. The problem statement, all variables and given/known data

see question 3a, b

2. Relevant equations

fn=(n/2L)(sqrt(F/(m/L))

3. The attempt at a solution

a)since this is a second harmonic, f2 = 2(2/L)(sqrt(F/(m/L)) = (1/L)(sqrt(F/(m/L))... wavelength = L

quadrupling F would mean that f=(1/L)(sqrt(4F/(m/L)) = (2/L)(sqrt(F/(m/L))

since f does not change, only way that these two will be equal is if the above is divided by 2

(2/2L)(sqrt(F/(m/L)) = (1/L)(sqrt(F/(m/L))

thus wavelength = 2L, so the new picture should just contain half of the wave?

b)tripling tension would mean that wavelength = sqrt(3)L... this shouldn't be possible right? since a standing wave needs to be connected at both ends (nodes) and having a wavelength of 1.7L would not connect on one end...

please help! thanks

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# Homework Help: Standing waves and tension

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