- #1
~angel~
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The expression T(tension)/(mu*f^2) shows that no matter what the tension, and frequency are, as long as there are the same amount of nodes in the string, the ratio is always the same.
The reason that the ratio in the previous part always comes out the same, regardless of which of the many possible configurations of the string that give four antinodes you chose, is that the ratio actually equals a much simpler quantity that will always be the same for configurations of the string that yield four antinodes. Which of the following gives that quantity? Here E is the energy of the wave, and A is the amplitude.
a.lambda b.lambda^2 c.E d.E^2 e.A f.A^2
I'm not sure what the answer is. Would someone please help.
Thanks.
The reason that the ratio in the previous part always comes out the same, regardless of which of the many possible configurations of the string that give four antinodes you chose, is that the ratio actually equals a much simpler quantity that will always be the same for configurations of the string that yield four antinodes. Which of the following gives that quantity? Here E is the energy of the wave, and A is the amplitude.
a.lambda b.lambda^2 c.E d.E^2 e.A f.A^2
I'm not sure what the answer is. Would someone please help.
Thanks.