# Standing waves in a pipe

1. Oct 10, 2014

### Karol

1. The problem statement, all variables and given/known data
What is the base frequency of a 20 cm pipe which is open on both ends.
Again but closed on one end.

2. Relevant equations
u=velocity, $\lambda$=wave length: $\lambda=\frac{u}{f}$
Velocity in air=348[m/sec]

3. The attempt at a solution
I understand these are standing waves in air.
In an open end there is a peak, so the first wavelength is $\lambda=2\cdot 20=40[cm]$
$0.4=\frac{348}{f_1}\rightarrow f_1=870[Hz]$
In the closed on one end condition, in the open end there is a peak and in the closed end a node, so the wavelength is $\lambda=4\cdot 20=80[cm]$
$0.8=\frac{348}{f_1}\rightarrow f_1=435[Hz]$
Both answers differ from the right ones by the same factor

2. Oct 11, 2014

Puzzling.