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Standing waves in a pipe

  1. Oct 10, 2014 #1
    1. The problem statement, all variables and given/known data
    What is the base frequency of a 20 cm pipe which is open on both ends.
    Again but closed on one end.

    2. Relevant equations
    u=velocity, [itex]\lambda[/itex]=wave length: [itex]\lambda=\frac{u}{f}[/itex]
    Velocity in air=348[m/sec]

    3. The attempt at a solution
    I understand these are standing waves in air.
    In an open end there is a peak, so the first wavelength is [itex]\lambda=2\cdot 20=40[cm][/itex]
    ##0.4=\frac{348}{f_1}\rightarrow f_1=870[Hz]##
    The answer should be 1140[Hz]
    In the closed on one end condition, in the open end there is a peak and in the closed end a node, so the wavelength is [itex]\lambda=4\cdot 20=80[cm][/itex]
    ##0.8=\frac{348}{f_1}\rightarrow f_1=435[Hz]##
    The answer should be 570[Hz]
    Both answers differ from the right ones by the same factor
     
  2. jcsd
  3. Oct 11, 2014 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    Puzzling.
     
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