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Standing waves super basic im dumb

  1. Mar 10, 2013 #1
    1. The problem statement, all variables and given/known data

    The 4th node of a standing wave occurs at a position of 4.10 meters. Where is the 2nd antinode?

    2. Relevant equations

    nodes occur at: x=n*(λ/2)
    antinodes: x=(n+.5)*(λ/2)

    3. The attempt at a solution
    n=4??
    4.1m=2λ→λ=2.05m
    now n=2??? x=(2+.5)*(λ/2)≈2.56m wrong!
    x=1.54m
     
  2. jcsd
  3. Mar 11, 2013 #2

    PeterO

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    No answer to that question as it stands.

    Was there any particular feature of the standing wave at position 0.00 metres?
     
  4. Mar 11, 2013 #3
    I didn't get any more info. the solution has a sin graph I think with the 2nd antinode as the 2nd max which mazes sense, so 1.5*wavelength/2. But I can't figure out why the equation won't work. Thanks for your help btw. I'll take a look at you question.
     
  5. Mar 11, 2013 #4

    PeterO

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    This standing wave ..

    Is it on a string, fixed at one end at 0.00

    Is the standing wave in an open pipe? An open pipe that runs form 0.00m to some distant point?

    Is this standing wave in a stopped pipe? A stopped pipe with its stopped end at 0.00?
     
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