# Stange proof!

1. Feb 5, 2010

### typhoonss821

One of Maxwell's equations says that $$\nabla\cdot\vec{B}{=0}$$ where B is any magnetic field.
Then using the divergence theore, we find
$$\int\int_S \vec{B}\cdot\hat{n}dS=\int\int\int_V \nabla\cdot\vec{B}dV=0$$.

Because B has zero divergence, there must exist a vector function, say A, such that
$$\vec{B}=\nabla\times\vec{A}$$ .
Combining these two equations, we get
$$\int\int_S \hat{n}\cdot\nabla\times\vec{A}dS=0$$ .
Next we apply Stoke's theorem and the preceding result to find
$$\oint_C\vec{A}\cdot\hat{t}ds=\int\int_S\hat{n}\cdot\nabla\times\vec{A}dS=0$$ .
Thus A is path independent. It follows that we can write
$$\vec{A}=\nabla\psi$$ , where Ïˆ is some scalar fution.

Since the curl of the gradient of a function is zero, we arrive at the remarkable fact that
$$\vec{B}=\nabla\times\nabla\psi=0$$
that is, all magnetic field is zero!

Wow, there must be someting wrong...

My thought is that we can not apply Stoke's theorem in this case because the region we discuss is not simply connected.