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Stat #4

  1. Feb 13, 2006 #1
    I want to just do this, but I don't think I can:

    The Agronomist finds an average of 2 shrubs per 1 acre jojoba. μ = 2

    The probability is given by: μ = np, hence: p = (μ/n)

    a.) (1) p = (2/5) = 0.4 (2) p = (2)/(5/2) = 0.8 (3) p = 1.2

    120% does not seem rational. If its going to happen, it should be 100% at most.
    Last edited: Feb 13, 2006
  2. jcsd
  3. Mar 30, 2006 #2

    First things first,definitions! Let X be the random variable for the number of shrubs per acre of jojoba.

    In my opinion, X should follow a Poisson distribution, as there is theoretically no limit to the number of shrubs we can find, instead of a Binomial model as seen in your calculations. Hence, [tex] X \sim P_0(2) [/tex]
    With this, you should be able to proceed with your working for (a).

    As for part (b), I think we should pay some attention to the word "next". This probably means that there is some restriction on the probability. I think the question means that the agronomist should find 5 plants in the first area of land... but which area (1, 2, or 3 acres) should we use?
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