What are the equations for static and kinetic coefficents of friction?

[NewJersey]

A Force 75.0 N is required to set a 25.0kg block into motion and a froce of 60.0N is required to leep it in motion at a constant velocity

a) The static coefficent of friction is ?
b) The kinetic coeficent of friction is ?

Help

 

[firefly_1]

Do you know the equations that are needed to find both that static and kinetic coefficents? You have the initial maximum force and the sliding kinetic force as well as the of the object. These three pieces of information are all you will need to find the two coefficents.

 

[ogb p]

The equations for static and kinetic coefficients of friction are as follows:

a) The static coefficient of friction is equal to the maximum static friction force (F_s) divided by the normal force (N) acting on the object. This can be represented as μ_s = F_s/N.

b) The kinetic coefficient of friction is equal to the kinetic friction force (F_k) divided by the normal force (N) acting on the object. This can be represented as μ_k = F_k/N.

In this scenario, we can use the given information to solve for the coefficients of friction.

a) To find the static coefficient of friction, we can use the equation μ_s = F_s/N. We know that a force of 75.0 N is required to set the 25.0 kg block into motion. Therefore, the maximum static friction force (F_s) is equal to 75.0 N. The normal force (N) acting on the block is equal to its weight, which can be calculated as mg = (25.0 kg)(9.8 m/s^2) = 245 N. Plugging these values into the equation, we get μ_s = 75.0 N/245 N = 0.306.

b) To find the kinetic coefficient of friction, we can use the equation μ_k = F_k/N. We know that a force of 60.0 N is required to keep the block in motion at a constant velocity. Therefore, the kinetic friction force (F_k) is equal to 60.0 N. The normal force (N) is still equal to the weight of the block, which is 245 N. Plugging these values into the equation, we get μ_k = 60.0 N/245 N = 0.245.

In conclusion, the static coefficient of friction is 0.306 and the kinetic coefficient of friction is 0.245 in this scenario. These values represent the amount of friction present between the block and the surface it is resting on.