I've asked a similar question before in some way or another, I'm still troubled by it. Technically there is no such thing as a static electric field: Take for instance a parallel plate capacitor Argument #1: Electrons are always moving inside the conductor, they have a finite thermal energy, also skin depth penetration and electron electron interaction can also introduce motion, their movements can be averaged out in some quasi steady state at the macroscopic level to generate a "static field". The movements of these electrons can also generate radiation of varying frequency dependent on their accelerations. Argument #2: The electric field in QFT is mediated by virtual photons, real photons provide quanta of E/M radiation. Here is where my question lies. Can we say a "static electric" field is a superposition (fourier if you will) of different frequency photons that add up to a "static field"? If so..... Question 1: A sufficient static field can "classically" ionize an electron from an atom. If the static field is a superposition of many frequencies, (and since ionization can only occur once you reached ionization frequency QM), is it the higher frequency terms in the superposition that form the static field the "culprits" that are actually doing the ionization? If so.... then you should be able to ionize an atom with a low intensity static electric field, increasing the intensity would only increase the probability of higher order contributions ( you require more individual photons of many frequencies to reach the larger amplitude static field). But then ionization should be irrelevant of how strong your classical static E field is, (a problem), just more likely with a larger field. Question 2: Would a static electron (not moving) emit an electric field at all? Or is the electric only mediated because it gives off radiation due to its thermal motion or other acceleration, for a static charge should not emit E/M radiation, only E "technically", and if its moving it will emit E and M. Thank you very much to everyone.