Find Force of Tension on 2 Supporting Ropes | mg=98N

[yyttr2]

ok, I am preparing for a test and I can not find this explained simply online.

how do I find the force of tension on two ropes supporting a box (mg=98N) if the angle that the ropes form are not equal to one another?

please help? D:

 

[tiny-tim]

Hi yyttr2!

ok, I am preparing for a test and I can not find this explained simply online.

how do I find the force of tension on two ropes supporting a box (mg=98N) if the angle that the ropes form are not equal to one another?

Call one T₁ and the other T₂, and then either draw a vector triangle, or take components in some suitable direction (perpendicular to either string is fastest).

Why is that worrying you?

 

[sir-pinski]

To find the force of tension on the two supporting ropes, you will need to use trigonometric equations. First, draw a diagram of the situation with the box hanging from the two ropes. Label the known values, such as the weight of the box (mg=98N) and the angles formed by the ropes. Then, use the trigonometric ratios (sine, cosine, tangent) to calculate the force of tension on each rope.

Here is an example:

Let's say the angle formed by the first rope is 30 degrees and the angle formed by the second rope is 45 degrees. We can use the sine ratio to find the force of tension on each rope.

Sin 30 = opposite/hypotenuse
Sin 30 = Tension on first rope/98N
Tension on first rope = 98N x sin 30
Tension on first rope = 49N

Similarly, for the second rope:
Sin 45 = opposite/hypotenuse
Sin 45 = Tension on second rope/98N
Tension on second rope = 98N x sin 45
Tension on second rope = 69.3N

So, the force of tension on the first rope is 49N and the force of tension on the second rope is 69.3N.

Remember to always label your diagram and use the correct trigonometric ratio based on the given information. With practice, you will be able to solve these types of problems easily. Good luck on your test!