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## Homework Statement

A window cleaner of mass 95 kg places a 22kg ladder against a frictionless wall at a angle 65 degrees with the horizontal. The ladder is 10 m long and rests on a wet cloor with a coefficient of static friction equal to .40. What is the max lenght that the window cleaner can climb before the ladder slips?

## Homework Equations

sum F(x)=F(fr)-F(w)=0

sum F(y)=F(n)-mg=0

sum torque=F(w) * l (sin theta) - mg * 1/2 cos theta=0

## The Attempt at a Solution

F(w)=mg/2tan theta

=(117)(9.8)/2tan65

=1146.6/4.28

=267.89 N

F(n)=mg

=1146.6 N

maxF(fr)=mu* F(n)=mu*mg

F(w)=mg/2tan theta=mu*mg

=tan theta=1/2*mu

=tan theta=1.25

=theta=51.34 degrees

Now, I am lost. Can someone please help? THANKS!!