1. The problem statement, all variables and given/known data A window cleaner of mass 95 kg places a 22kg ladder against a frictionless wall at a angle 65 degrees with the horizontal. The ladder is 10 m long and rests on a wet cloor with a coefficient of static friction equal to .40. What is the max lenght that the window cleaner can climb before the ladder slips? 2. Relevant equations sum F(x)=F(fr)-F(w)=0 sum F(y)=F(n)-mg=0 sum torque=F(w) * l (sin theta) - mg * 1/2 cos theta=0 3. The attempt at a solution F(w)=mg/2tan theta =(117)(9.8)/2tan65 =1146.6/4.28 =267.89 N F(n)=mg =1146.6 N maxF(fr)=mu* F(n)=mu*mg F(w)=mg/2tan theta=mu*mg =tan theta=1/2*mu =tan theta=1.25 =theta=51.34 degrees Now, I am lost. Can someone please help? THANKS!!