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Lma12684
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Homework Statement
A window cleaner of mass 95 kg places a 22kg ladder against a frictionless wall at a angle 65 degrees with the horizontal. The ladder is 10 m long and rests on a wet cloor with a coefficient of static friction equal to .40. What is the max length that the window cleaner can climb before the ladder slips?
Homework Equations
sum F(x)=F(fr)-F(w)=0
sum F(y)=F(n)-mg=0
sum torque=F(w) * l (sin theta) - mg * 1/2 cos theta=0
The Attempt at a Solution
F(w)=mg/2tan theta
=(117)(9.8)/2tan65
=1146.6/4.28
=267.89 N
F(n)=mg
=1146.6 N
maxF(fr)=mu* F(n)=mu*mg
F(w)=mg/2tan theta=mu*mg
=tan theta=1/2*mu
=tan theta=1.25
=theta=51.34 degrees
Now, I am lost. Can someone please help? THANKS!