- #1

- 199

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How do I set this up? What equations should be used with this?

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- Thread starter needhelp83
- Start date

- #1

- 199

- 0

How do I set this up? What equations should be used with this?

- #2

- 157

- 0

The only equations you need are the ones for static equilibrium.

- #3

- 199

- 0

- #4

- 199

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What are your static equilibrium equations?

- #5

- 199

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I meant what are the static equilibrium equations that I need for this

- #6

- 132

- 1

what does static equilibrium mean?

- #7

- 20

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1.draw a free body diagram

2. in an equations u sum the forces (in this case in the vertical direction) and they add up to 0 since its static equilibrium

3. pick a Point on the free body diagram and sum the torques around it

I dont know if you learned this yet, but that is the way I do it. Im half confused abou the diagram so my answer was 1.73 kg

I am thinking that a force CG is applying up on the "leg", and so is the force of mass of weight x 9.8 through the cable/string, and that at the centre of the leg there is a gravitational force pulling down.

so i sum the forces in y direction: CG + (mass of weight)g - (mass of leg)g = 0

I dont know if im on the right track, but basically all forces add up to equal ZERO, cuz in static equilibrium NOTHING MOVES

its not FN = ma

- #8

- 157

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Once you have the diagram set up, you should see how to solve it. Anything else will just give too much of the problem away.

The equations of static equilibrium are the sum of x and y forces equal zero. Also the equation of moments or torques in your case.

- #9

- 199

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Et=(35.0 cm)(g)(x)-(15 kg)(80.5 cm)(g)

x=34.5 kg

Is this what you mean?

x=34.5 kg

Is this what you mean?

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