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Static Equilibrium of acrobat

  1. Nov 12, 2007 #1
    1. The problem statement, all variables and given/known data
    An acrobat hangs by his hands from the middle of a tightly strestched horizontal wire so that the angle between the wire and the horizontal is 9.15 degrees. If the acrobat's mass is 88.4kg, what is the tension in the wire? Answer in units of N.


    2. Relevant equations
    Sum of Fy =0
    Sum of Fx =0
    F= sqrt(Fx^2 + Fy^2)


    3. The attempt at a solution

    Fysin(9.15)-(88.4kg)(9.8m/s2)=0
    Fy=5447.879N

    Fxcos(9.15)-(88.4kg)(9.8m/s2)=0
    Fx=877.486N

    F= Sqrt(5447.879^2+ 877.486^2)
    F=5518.0945N
     
  2. jcsd
  3. Nov 12, 2007 #2
    draw a free body diagram and add the forces as vectors.
     
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