Here is the problem I am attempting to solve:(adsbygoogle = window.adsbygoogle || []).push({});

http://img227.imageshack.us/img227/2747/problempr4.jpg [Broken]

The large quadriceps muscle in the upper leg terminates at its lower end in a tendon attached to the upper end of the tibia. The forces on the lower leg when the leg is extended are modelled as shown whereTis the tension in the tendon,Cis the force of gravity acting on the lower leg, andFis the force of gravity acting on the foot. FindTwhen the tendon is at an angle of 25.0° with the tibia, assuming thatC= 30.0 N,F= 12.5 N, and the leg is extended at an angle of 40.0° with the vertical. Assume that the centre of gravity of the lower leg is at its centre and that the tendon attaches the lower leg at a point one-fifth of the way down the leg.

What I am uncertain is my method of solving this question. I'm quite sure that I'm missing something. Here is what I did:

Fnet = 0

Angle between quadricep and the dotted line is equal to 40.0°. Therefore, the angle between the quadriceps andTis equal to 65.0°.

0 = Tsin65.0° - C - F

T = 46.9 N

Merci d'avance!

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# Homework Help: Static Equilibrium Problem

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