# Static Equilibrium problem

1. Sep 7, 2013

### Woopydalan

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

So with this problem, I have been thinking about it. Since it is in equilibrium, I know the sum of forces and torques will be equal to zero. However, I'm not sure how the height, h, fits into this. I know the weights have a force and are a distance away from that fulcrum, d and 2d, so I could see those as torques, and the 800 N one at 2d should counteract the 200 N one at d, but I just don't see how h fits into this, which is what we aim to find.

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2. Sep 7, 2013

### Saitama

I am not sure but try considering h as the height of rightmost pulley.

3. Sep 7, 2013

### ehild

This is not a rigid-body problem. The masses are connected to a string, and the tension of the string counteracts with the weights. Draw the free body diagram for both weights.

ehild

4. Sep 8, 2013

### Woopydalan

can you explain to me the difference between a ''rigid-body problem'' and a non-rigid body problem? Also, with my free body diagram, I see the tensions are to counteract the weights, but I have no other equations. How does d come into play with the problem in order to get closer to solving for h?

5. Sep 8, 2013

### SteamKing

Staff Emeritus
Do you understand how to resolve a force into its components? For instance, the weight W puts a tension on the rope holding up load P? What are the components of the tension in the rope?

6. Sep 8, 2013

### ehild

The string and the two weights do not make a rigid body, that keeps shape during motion.
The forces of the string have both horizontal and vertical components. For equilibrium, both components of the net force have to cancel at each weight. The components depend on the angle the string makes with the horizontal. How does that angle depend on h and d?
You can take the tension equal everywhere along the string. That gives two equations for the unknown tension and h.

ehild

7. Sep 8, 2013

### Woopydalan

Here is my attempt

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8. Sep 8, 2013

### ehild

Your solution is not correct. The tension acts along the string at the point where it is attached to the object. The tension is the same along the whole string, at both sides of the pulley. If there are two strings, both exert force.

ehild

9. Sep 8, 2013

### Woopydalan

When you say two strings, are you referring to the string attached to the 200 N crate? it looks like there is only 1 string throughout the whole drawing unless you consider that one. If it is a separate string, is its tension separate from the one connecting the two pulleys?

10. Sep 8, 2013

### ehild

You are right, it is the same string at both sides of the middle pulley, but two pieces, and the same tension in both. Both pieces act on the pulley and balance the force of the vertical string attached to the 200 N crate.
The tension in the vertical string balances the weight of 200 N.

ehild

11. Sep 8, 2013

### Woopydalan

Ok, so here is my 2nd attempt.

#### Attached Files:

• ###### 2.54 attempt 2.pdf
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186.3 KB
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49
12. Sep 9, 2013

### ehild

Again, you ignored that there are two forces from the string balancing the vertical force of 200 N.

ehild

13. Sep 9, 2013

### Woopydalan

Ok, now I think I understand what you wrote. I think this one is a good one, I finally considered the string on both sides of the middle pulley

#### Attached Files:

• ###### 2.54 attempt 3.pdf
File size:
189.8 KB
Views:
54
14. Sep 9, 2013

### ehild

It looks correct now.

ehild

15. Sep 9, 2013

### Woopydalan

Thanks for the help!

16. Sep 9, 2013

### ehild

You are welcome.

ehild