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Static Equilibrium.

  1. Nov 10, 2015 #1
    1. The problem statement, all variables and given/known data

    rHgvVyw.png

    2. Relevant equations


    3. The attempt at a solution

    8)
    The mass is in static equilibrium meaning the sum of all the forces acting on it are equal to 0.
    Both sides are holding have the same tension because they have the same angle.
    SINΘ = (Opposite) / Hypotenuse
    = Hypotenuse = (Opposite) / SINΘ
    = 20) / (SIN 30)
    = 20 / 0.5
    = 40

    The tension in the rope equals 40 N?

    9)
    I'm totally clueless where to start on this one.
    I'm totally guessing here but It must have something to do with the man weighing 700 N within the first 2M.
    So rope X must have higher tension.
     
  2. jcsd
  3. Nov 10, 2015 #2
    In 9 you have to do like you did in 8 and use the idea that the net force on the beam is zero. This will not tell you, however, the magnitude of the tension force in each rope, only their sum. But that is the first step. The next step is to use the idea that the net torque on the beam is zero.
     
  4. Nov 10, 2015 #3

    SteamKing

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    By using the sine of the angle here, are you calculating the tension in the line, or something else?

    Remember, the tension in each line will form the hypotenuse of the force triangle.
     
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