- #1
MPat
- 15
- 1
Homework Statement
A uniform vertical beam of mass 40kg is acted on by a horizontal force of 520N at its top and is held, in the vertical position, by a cable as shown.
a) Draw a free body diagram for the beam, clearly labelling all the forces acting on it
b) Calculate the tension in the cable.
c) Determine the reaction forces acting on the beam by the ground.
Homework Equations
ΣFx = 0
ΣFy = 0
Στ = 0
The Attempt at a Solution
a) I can't seem to add images to this. Whenever I try it only gives me the option of adding an image url which I don't have. Maybe someone can tell me how to do that!
For the image provided the uniform beam is standing up right (height of 5m). Force applied (520 N) acts on the top end of the beam to the left. A cable attaches the beam from 3m height down to the ground on the right. The angle between the ground and the cable is 28degrees.
In my free-body diagram I have the following forces acting on the beam.
Fa = 520N
Force tension from the cable
mg
Fn
Am I missing a force here? Should there be a force of friction between the beam and the ground? The question does not explicitly state anything about that.
b)
ΣFx = Ftx - Fa = 0
ΣFy = Fn-mg-Fty=0
Στ = Fa * 2 = 0
where the axis is located where the cable attaches to the beam at 3m. Ft does not create a torque force as it acts at the axis, and mg and Fn also do not create a torque force as the act directly away from the axis
I get here and I realize something is missing...based on the torque equation Fa would = 0, but Fa is given as 520N. Here's where I'm confused.
Please help!
Thanks