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Ʃτ = 0
ƩF = 0
summing the torques for each piece, i found
Ʃτ = MgLsin(90ψ)  mgIsin(ψ) = 0
MgLsin(90ψ) = mgIsin(ψ)
ML/mI = sin(ψ)/sin(90ψ) = sin(ψ)/cos(ψ) = tan(ψ)
so ψ = tan^{1}(ML/mI)
i don't know if this is correct or not...
and I have no idea how I could find the angle without considering torque. any help is appreciated. thanks :)
Homework Equations
Ʃτ = 0
ƩF = 0
The Attempt at a Solution
summing the torques for each piece, i found
Ʃτ = MgLsin(90ψ)  mgIsin(ψ) = 0
MgLsin(90ψ) = mgIsin(ψ)
ML/mI = sin(ψ)/sin(90ψ) = sin(ψ)/cos(ψ) = tan(ψ)
so ψ = tan^{1}(ML/mI)
i don't know if this is correct or not...
and I have no idea how I could find the angle without considering torque. any help is appreciated. thanks :)
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