1. The problem statement, all variables and given/known data A 230-l steel drum is completely full of gasoline. What total volume of steel material can be used in making the drum if the gasoline filled drum is to float in fresh water with the whole volume immersed? 2. Relevant equations ρwater=1000 kgm^-3 ρgasoline=680 kgm^-3 ρsteel = 7800 kgm^-3 3. The attempt at a solution Fb=mdrum*g ρwater*Vdrum=msteel+mgasoline ρwater*(Vsteel+Vgasoline)=(ρV)steel+(ρV)gasoline Then taking Vsteel subject and substituting with ρgasoline = 230*10^-3 Is this method correct ? I don't know whether the 230-l is the total volume of the drum or is it just the volume of gasoline?