1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Statics and Friction 01

  1. Jun 30, 2009 #1
    1. The problem statement, all variables and given/known data

    DSCF0001.jpg

    2. Relevant equations

    F = uR

    3. The attempt at a solution

    I don't understand the followings:

    For equilibrium at A, the equation should be F1 = T sin [tex]\theta[/tex]. Am I right?

    While for the one at B, the equation should be F2 = T sin [tex]\theta[/tex]. Am I right?

    In addition, how can I get cos [tex]\theta[/tex] = (au2 + 1)-0.5 at the last answer?

    Thank you very much!
     
  2. jcsd
  3. Jul 1, 2009 #2
    I tried some methods and found the followings finally:

    tan [tex]\theta[/tex] = 3u = 3u / 1

    Put the above result to a right-angled triangle with adjacent side = 1 and opposite side = 3u,

    we can get cos [tex]\theta[/tex] = (9u2 + 1)-0.5.

    I guessed that the "a" is actually a "9" which is a typo instead. Am I right?
     
  4. Jul 2, 2009 #3

    Shooting Star

    User Avatar
    Homework Helper

    You seem to be quite right.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Statics and Friction 01
  1. Static friction (Replies: 12)

  2. Static friction (Replies: 6)

  3. Static friction? (Replies: 8)

Loading...