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Statics: Equilibrium of Machines

  1. Oct 22, 2005 #1
    The problem is stated in the picture. And I drew the FBDs of the top half of the bolt cutter, as shown in the second page:

    Setting moment about A to be 0, I obtain -Q(1 in)-FBy*4 in=0
    And By= -Q/4 lb

    Then setting moment about C to be zero. I obtain
    FBy(0.5 in)-20 in(75 lb)=0
    Substitute in By, I get the magnitude of Q to be 12000 lb.

    UPDATE: PICS
    Problem:
    http://img368.imageshack.us/img368/7535/1239zw.jpg
    FBD's:
    http://img368.imageshack.us/img368/431/22cm.jpg


    Am I correct?
     

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    Last edited: Oct 22, 2005
  2. jcsd
  3. Oct 22, 2005 #2

    Pyrrhus

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    What was the problem then?, it looks good to me (the procedure, i didn't do the arithmetic).
     
  4. Oct 23, 2005 #3
    The problem just seems...too easy...
     
  5. Oct 23, 2005 #4

    Pyrrhus

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    I was checking the problem again you forgot the Bx component when you did moment about C, it does have a moment, and the lever arm for 75 about c is 19.5
     
  6. Oct 27, 2005 #5
    AE is 2-force member (so the reaction at A is only Ay), so that Bx is actually zero (due to the equilibrium eqs of AB). Then you can solve the rest of them.
     
    Last edited: Oct 27, 2005
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