- #1

June W.

- 13

- 0

## Homework Statement

This problem is from WileyPLUS. I've been looking through my book, but none of the methods they present work for me. I guess I just don't know how to use them properly.

Determine the moments of the 5.6-kN force about the point

*O*and about point

*B*.

## Homework Equations

I know I can split

**F**into its X and Y components by using

**F**sin(theta) and

**F**cos(theta).

## The Attempt at a Solution

I think if I multiply the X and Y components of

**F**by the corresponding coordinate distances between point A and B or A and O and add what I get, I should get the moment but for some reason this isn't giving me the right answer:

9sin(24) + (-11)cos(24) = -6.388

-6.388 * -5.6 = 35.77

and

-4sin(24) + (-11)cos(24) = -11.676

-11.676 * -5.6 = 65.39

All the website tells me is that these answers are wrong. Any help is greatly appreciated! Thanks!