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A big HI to everyone in the forum. Im new to this awesome forum. Perfect for my engineering studies! :)

Anyway, heres my problem.

The cords BCA and CD can each support a maximum load of 500N. Determine the maximum weight of the crate(A) that can be hoisted at a constant velocity, and the angle 0 for equilibrium.

What I've done:

Using the equations of equilibrium,

[tex]\sum[/tex]Fx=0

DC cos (angle) = CB sin 22.6

500N cos (angle) = 500 sin 22.6

angle = 67.4

[tex]\sum[/tex]Fy=0

DC sin (angle) - CB cos 22.6 = A

500 sin 67.4 = A + 500 cos 22.6

A = 0.1N (a value which does not seems right to me)

Anyway, heres my problem.

The cords BCA and CD can each support a maximum load of 500N. Determine the maximum weight of the crate(A) that can be hoisted at a constant velocity, and the angle 0 for equilibrium.

What I've done:

Using the equations of equilibrium,

[tex]\sum[/tex]Fx=0

DC cos (angle) = CB sin 22.6

500N cos (angle) = 500 sin 22.6

angle = 67.4

[tex]\sum[/tex]Fy=0

DC sin (angle) - CB cos 22.6 = A

500 sin 67.4 = A + 500 cos 22.6

A = 0.1N (a value which does not seems right to me)

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