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A big HI to everyone in the forum. Im new to this awesome forum. Perfect for my engineering studies! :)
Anyway, heres my problem.
The cords BCA and CD can each support a maximum load of 500N. Determine the maximum weight of the crate(A) that can be hoisted at a constant velocity, and the angle 0 for equilibrium.
What I've done:
Using the equations of equilibrium,
[tex]\sum[/tex]Fx=0
DC cos (angle) = CB sin 22.6
500N cos (angle) = 500 sin 22.6
angle = 67.4
[tex]\sum[/tex]Fy=0
DC sin (angle)  CB cos 22.6 = A
500 sin 67.4 = A + 500 cos 22.6
A = 0.1N (a value which does not seems right to me)
Anyway, heres my problem.
The cords BCA and CD can each support a maximum load of 500N. Determine the maximum weight of the crate(A) that can be hoisted at a constant velocity, and the angle 0 for equilibrium.
What I've done:
Using the equations of equilibrium,
[tex]\sum[/tex]Fx=0
DC cos (angle) = CB sin 22.6
500N cos (angle) = 500 sin 22.6
angle = 67.4
[tex]\sum[/tex]Fy=0
DC sin (angle)  CB cos 22.6 = A
500 sin 67.4 = A + 500 cos 22.6
A = 0.1N (a value which does not seems right to me)
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