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Statics: Mechanical Equilibrium

  • Thread starter teknodude
  • Start date
  • #1
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I need some help in this problem to see if my game plan is right. My answer doesn't make sense, well to me it doesn't.

A weight of 200 lb hangs from a frame of negligible weight, as shown. If the frame is in equilibrium, determine the loads acting on the frame at A and D. Use the fact that the frame acts as a three-foce element to check your answer.

-they are all pin connections
-theres a 45 45 90 degree triangle there.

First off i drew a FBD for just DB, and found that it is a two force element, so the line of action passes through the force points of application.

Then when i draw a FBD for ABC the forces at B, it is just a force pointing at a 45 degree angle. Then theres a force Ay and Ax at A and the 200 lb force acting downward at C.

the sum of the forces in the x direction

-Ax -B cos45 = 0

The sum of the force in the y direction

Ay + B sin45 - 200 lb = 0

The sum of the moments in the z direction at point A

-(6ft)(200lb) + (3ft)(Bsin45) = 0
 

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Answers and Replies

  • #2
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ok i think i'm using the idea of a 2-force element wrong.


The diagram that i have there needs to be zoomed in a bit, doesn't seem to show up right cause some browsers resize it.
If you need a better diagram then i'll try to scan it this time instead of using paint.
 
  • #3
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Member DB is a two force member, that makes the analysis simple.
 
  • #4
157
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At A, for the force i get

0 for the x component
200 lb for the y component

anyone else get these values at point A?
 
  • #5
2,985
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no, Fax=400lb, Fay= 200N down
 
  • #6
Answer

If anyone ever needs the solution, I'd be more than happy to help you come to it
 
  • #7
157
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I got it. I was making this problem more harder than it seemed :cry:
 

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