- #1

- 157

- 0

I need some help in this problem to see if my game plan is right. My answer doesn't make sense, well to me it doesn't.

A weight of 200 lb hangs from a frame of negligible weight, as shown. If the frame is in equilibrium, determine the loads acting on the frame at A and D. Use the fact that the frame acts as a three-foce element to check your answer.

-they are all pin connections

-theres a 45 45 90 degree triangle there.

First off i drew a FBD for just DB, and found that it is a two force element, so the line of action passes through the force points of application.

Then when i draw a FBD for ABC the forces at B, it is just a force pointing at a 45 degree angle. Then theres a force Ay and Ax at A and the 200 lb force acting downward at C.

the sum of the forces in the x direction

-Ax -B cos45 = 0

The sum of the force in the y direction

Ay + B sin45 - 200 lb = 0

The sum of the moments in the z direction at point A

-(6ft)(200lb) + (3ft)(Bsin45) = 0

A weight of 200 lb hangs from a frame of negligible weight, as shown. If the frame is in equilibrium, determine the loads acting on the frame at A and D. Use the fact that the frame acts as a three-foce element to check your answer.

-they are all pin connections

-theres a 45 45 90 degree triangle there.

First off i drew a FBD for just DB, and found that it is a two force element, so the line of action passes through the force points of application.

Then when i draw a FBD for ABC the forces at B, it is just a force pointing at a 45 degree angle. Then theres a force Ay and Ax at A and the 200 lb force acting downward at C.

the sum of the forces in the x direction

-Ax -B cos45 = 0

The sum of the force in the y direction

Ay + B sin45 - 200 lb = 0

The sum of the moments in the z direction at point A

-(6ft)(200lb) + (3ft)(Bsin45) = 0

#### Attachments

Last edited: