# Homework Help: Statics Problem - Not sure why answer is answer

1. Sep 16, 2009

### akhmed966

http://img10.imageshack.us/img10/8880/capturejfu.jpg [Broken]

I did arctan(12/5) to get the degrees + 180 to get the angle from the X axis to B, then I just split the angles into components.

I did 100*cos(246) + 100*cos(theta) = 0, and I got 67 degrees.
Then I was doing the Y components, and realized they were equal and opposite, so it would equal 0, which the weight can't be equal to.

So I looked at the solution, and here how the answer is found.

Sum of X: 100cos(theta) = Wa(5/13)
Sum of Y: 100sin(theta) = Wa(12/13)+Wa

Why is the answer figured like this, and when do I do it differently from sum of the components? I'm totally lost, but I have a slight idea.

Thanks.

Last edited by a moderator: May 4, 2017
2. Sep 16, 2009

### CFDFEAGURU

Why, did you add the 180 degrees? Assuming the x axis is at the center of the pully the angle is simply tan^-1(12/5)?

Also, draw a simple free body diagram to find the force vector components. You will find the actual numerical value of the angle is not needed.

Thanks
Matt

Last edited: Sep 16, 2009
3. Sep 16, 2009

### akhmed966

I meant the positive X axis.

Also, I did draw a free body diagram, but I am not sure why I couldn't add the sum of the components.

4. Sep 17, 2009

### PhanthomJay

You seem to be assuming that the tension in cord CD and BC are both 100 lbs. That is not correct. Also, you are not noting that the tension in cords draped around frictionless ideal pulleys are the same on both sides of the wrap (that is, Tension in AC = Tension in BC). Draw an FBD of the hanging weight, and redo your FBD of the pulley at joint C.

5. Sep 18, 2009

### akhmed966

The tension in AC = BC? Do you mean the tension in BC = DC?

I still don't see how the equation was formed, could someone explain how the equation was determined?

6. Sep 18, 2009

### PhanthomJay

Yes. The cord ACB is one continuous chord wrapped around an ideal pulley, in which case AC = BC.
No.
The system is in equilibrium. Draw a FBD of the weight to determine that the tension in AC must be W_a. Then draw an FBD of the pulley at C, and you should be able to get the same equations as the book's to solve for theta and W_a. Which cord do you think has the 100 pound tension load?.

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