A uniform ladder of mass m = 30.0 kg and length l = 2.50 m leans against a frictionless vertical wall. The ladder forms an angle theta = 75.0 degrees with the rough floor. The coefficient of static friction μ between the floor and the ladder is equal to 0.288. Determine the force Fw exerted on the ladder by the wall, and the frictional force f that the floor exerts on the ladder. So here's my force diagram: http://imageshack.us/photo/my-images/90/gha.png/ Here are my equilibrium equations: Fnet,x = Fw - f = 0 Fnet,y = Fv - mg = 0 Tnet,z = -(Fw)(2.4148) + (mg)(0.3235238) = 0 From the sum of the torques, I found Fw: Fw = [(mg)(0.3235236)] / (2.4148) = 39.4 N. Fw = f = 39.4 N. What did I do wrong?