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Statics Table Questions

  1. Apr 8, 2013 #1
    1. The problem statement, all variables and given/known data

    Screen Shot 2013-04-09 at 12.42.13 PM.png


    2. Relevant equations

    Free Body Diagrams, Moments, Equilibrium

    3. The attempt at a solution

    Started off by giving x,y,z coordinates to the 4 points (A,B,C,E). E is the centre of the table and I used that as my origin.

    A=(-1.034, 0, -0.6) [Leg to the Left)
    B=(1.034, 0, 0.6) [Furthest Leg]
    C=(0,0,1.2) (Leg Closest)
    E=(0,0,0)

    From there, I knew that the table was exerting a force of 147.15 N (15 x 9.81) downwards over it's whole area. So to find the force it exerted at it's centre of gravity, I then multiplied this value by the surface. (Is this correct Methodology?)

    So at Point E their was a downwards force of 166.423 N.

    From there, I did a free body diagram and calculated Vertical Force Equilibrium of the System. So I got 166.423 = Av, Bv, and Cv.

    I then went on to calculate moment equilibrium but got stuck as i pondered the next question:

    what constitutes as the table flipping over or failing?. My first approach was to look for the point at which their is an imbalance in the system. But this would constitute any force acting upon the system. Not the 300N load at 0.447m from the origin as stipulated in the answer!

    How do i approach this question? I seem to have something fundamentally wrong

    Cheers
     
  2. jcsd
  3. Apr 9, 2013 #2

    SteamKing

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    Staff Emeritus
    Science Advisor
    Homework Helper

    Look at the reaction in Leg B as P moves further away from the center of the table. Is there a distance x from the center where P is applied at which the reaction at B vanishes?
     
  4. Apr 14, 2013 #3
    Another helpful principle is that the position of the applied load must be equal and opposite to the centroid of the reaction forces.
     
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