This should be a very easy problem, i just can't seem to find what makes the center, shape and spread. The distribution of actual weights of 8-ounce chocolate bars produced by a certain machine is normal with mean 8.1 ounces and standard deviation 0.1 ounces. Company managers do not want the weight of a chocolate bar to fall below 7.85 ounces, for fear that consumers will complain. Four candy bars are selected at random and their mean weight, x-bar, is computed. Describe the center, shape, and spread of the sampling distribution of x-bar. My method: Mean of x-bar = Mean So, the mean of x-bar = 8.1 ounces Standard Deviation of x-bar = (standard deviation)/sqrt(n) So, 0.1/sqrt(4) = 0.1/2 = 1/20 Okay, now the distribution curve for x-bar is going to have the characteristics of mean = 8.1 and standard deviation = 0.05. I've gotten that far, but now i don't know how to describe the center (I'm assuming this is 8.1?), shape, and spread or the distribution curve? Any help?