(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Three cards are dealt from a well-shuffled deck.

(a) Find the chance that all of the cards are diamonds.

(b) Find the chance that none of the cards are diamonds.

(b) Find the chance that the cards are not all diamonds.

2. Relevant equations

Not sure ...

3. The attempt at a solution

There are 52 cards in a deck. The chance of one being a diamond is 13/52. If you know that one card you were dealt is a diamond, then the chance of another being a diamond is 12/51, since there is 1 less card and 1 less diamond. And if you that two cards are diamonds, then the chance of a third being a diamond is 11/50. The chance of 3 cards being diamonds is therefore (13/52)*(12/51)*(11/50). Part (b) can be solved similarly. This time the chance is 39/52, then 38/51, then 37/50, and the chance of the three happening is (39/52)*(38/51)*(37/51). Part (c) is simply the opposite of part (a).

Am I right?

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# Homework Help: Statistics Question

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