A car rental company receives cars at n = 1000 cars/year for the first 5 years and none thereafter. The pdf for retiring a car is, Code (Text): p(t) = (1/5)(1 - exp(-t/3)) , 0<t<5 = (1/5)(exp[-(t-5)/3] - exp(-t/3)) , t > 5 Show that after 6 years cars are being retired from the scheme at approxiamtely 11 per week. To answer that I did, N = int[t1 to t2] t*p(t) dt where t1 = 6 (years) t2 = 6 1/52 (years) and N would be the number of retired cars during that week. I thought that was how I was supposed to do it. Is that correct ? When I worked out that integral, I got N = 0.0134. How do I get 11 as the answer ? Where does the n = 1000 come into it, if at all ?