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Stats Help

  1. Mar 16, 2006 #1
    Okay so I did this problem and got it wrong but I get one more chance to get it right. I tried using Binomial Dist to solve it but I failed.

    30% of all M&Ms are brown. If 7 M&Ms are randomly selected, what is the probability that at most 1 is brown?

    I thought I would use 0 and 1 but I guess not. Can someone help me?
     
  2. jcsd
  3. Mar 17, 2006 #2

    mathman

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    p0=.37
    p1=7*.36*.7

    Add them up.
     
  4. Mar 19, 2006 #3

    mathman

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    Sorry, got the probs reversed. switch .3 and .7.

    p0=.77
    p1=7*.76*.3

    Add them up.
     
  5. Apr 16, 2006 #4
    For Binomial Distribution,
    take n=7, p=0.3, q=1-p=0.7.

    P(X<=1)=P(X=0)+P(X=1)=q^7+n*p*q^6

    thts it gys...
    enjy
     
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