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Stats Norm dist, std dev, mean z score find x

  1. Sep 27, 2012 #1
    1. The problem statement, all variables and given/known data
    So the question is, given a set of random numbers, find the mean and the value that will be >= 99% of the occurances. So for a set of random numbers between say, 1-100, if the mean is 50, how do I find out what number will be >= 99% of all observations of the time.

    Havent taken stats in a long time. No book provided.

    2. Relevant equations

    99% has a z score of 2.576
    Somehow I have to turn that into a number using standard deviation.

    3. The attempt at a solution
    z=(x-m)/stdev
    x=(stdev*z)+mean
    is x the number I am looking for???

    Thanks all!
     
  2. jcsd
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