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Stats question regarding mean

  1. Apr 24, 2007 #1


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    [Solved]Stats question regarding mean

    1. The problem statement, all variables and given/known data
    Yo.Exam marks,X've mean 70 and standard deviation 8.7.The marks need to be scaled using the formula Y=aX+b so that the scaled marks,Y've mean 55 and standard deviation 6.96.Find the values of a and b.*From the answer sheet -to form equation for mean it's 55=70a+b,why is there "b" in there?

    2. Relevant equations

    3. The attempt at a solution

    U don't need this,I just need some clarity on the above * thing.Pls?
    Last edited: Apr 24, 2007
  2. jcsd
  3. Apr 24, 2007 #2


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    Staff Emeritus
    Science Advisor

    The formula for mean is "linear"- add the values and divide by n- which means that if Y= aX+ b, then mean(Y)= a*mean(X)+ b so your first equation is a(70)+ b= 55.

    Formula for standard deviation is "root-mean-square":
    [tex]\sqrt{\Sigma \frac{(X-\mu)^2}{n}}[/tex]
    so the standard deviation of Y= aX+ b is
    [tex]\sqrt{\Sigma \frac{((aX+b)-(a\mu+b))^2}{n}}= \sqrt{\Sigma\frac{a^2(x-\mu)^2}{n}}= a\sigma[/tex]
    where [itex]\mu[/itex] and [itex]\sigma[/itex] are the mean and standard deviation of X respectively. Since the stadard deviation of X is 8.7 and you want the standard deviation of Y to be 6.96, you must have 6.96= a(8.7).

    It should be easy to solve the equations 70a+ b= 55 and 8.7a= 6.96 for a and b.
  4. Apr 24, 2007 #3


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    Thanx so much for ur stuff and kind,clear explanations.Solved.Cya.~The End~
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