Hi, first post so here goes:(adsbygoogle = window.adsbygoogle || []).push({});

I'm having a little trouble with a question on my tutorial, and im not sure what to do. Here it is:

Steam under steady flow conditions has the following states:

Initial Conditions:

Pressure - 47 Bar

Spec Volume - 0.09957 m^3 / kg

Internal energy - 3420 kJ/kg

Velocity - 21 m/s

Final Conditions:

Pressure - 10 Bar

Spec Volume - 0.1636 m^3 /kg

Internal Energy - 2440 kJ/kg

Velocity - 38 m/s

Heat is added to the surroundings at the rate of 0.75 kJ/s, if the rate of steam flow is 0.36kg/s calculate the rate of work transfer

I have been given the formula:

(C1^2 /2) + u1 +p1v1 + q =(C2^2 /2) +u2 +p2v2 + w

thanks for any help in advance,

chris

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# Homework Help: Steady Flow Energy Equation

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