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Steam plant question.

  • #1
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Im attempting this question for an evening class im attending. hope im posting in the right place. I'm not sure where I have gone wrong think its where I rearranged my formula to find steam output.

Question attached below
 

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Answers and Replies

  • #2
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The work is a bit unclear. I'll get back to you in a day or so.
 
  • #3
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Ok Thanks
 
  • #4
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I think I calculated the steam output wrong, I have the over all efficiently of the system 77%, what formula do I use the calculate steam output?



Q=M(h2-h1)
 
  • #5
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Yeah that's the one..!
For calculating the steam output, you can directly use the 77% efficiency without involving the economizer and super heater (if I'm not wrong).
So 77% of the heat obtained from the combustion of coal is used to convert water to steam.
 
  • #6
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Yeah that's the one..!
For calculating the steam output, you can directly use the 77% efficiency without involving the economizer and super heater (if I'm not wrong).
So 77% of the heat obtained from the combustion of coal is used to convert water to steam.
77% is the overall efficiency am I right ? So did I divide .77 by h2-h1 to get steam output?
 
  • #7
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77% is the overall efficiency am I right ? So did I divide .77 by h2-h1 to get steam output?
Yes! And equate it with the energy provided by the combustion of coal. Tell me if that gives the right answer.
 
  • #8
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6244.09 kg/h
 
  • #9
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I meant did you get the right answer?
 

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