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Steel Ball off the Wall

  1. Mar 18, 2007 #1
    A 9 kg steel ball strikes a wall with a speed of 10 m/s at an angle of 49.8 degrees with the normal to the wall. It bounces off with the same speed and angle. If the ball is in contact with the wall for .0911 sec, what is the magnitude of the average force exerted on the ball by the wall?

    KE = 1/2 m v^2 p = mv

    I wasn't sure how to tackle this one, I made a few attempts but to no avail. Can anyone learn me up a bit.
     
  2. jcsd
  3. Mar 18, 2007 #2

    hage567

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    Look up the impulse-momentum theorem.
     
  4. Mar 18, 2007 #3
    Thanks, that helped alot. I found the change in the x component of the momentum then divided by the time.
     
  5. Mar 18, 2007 #4

    hage567

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    That sounds good to me. :smile:
     
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