Steel Ball off the Wall

  • Thread starter Gammage
  • Start date
  • #1
14
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A 9 kg steel ball strikes a wall with a speed of 10 m/s at an angle of 49.8 degrees with the normal to the wall. It bounces off with the same speed and angle. If the ball is in contact with the wall for .0911 sec, what is the magnitude of the average force exerted on the ball by the wall?

KE = 1/2 m v^2 p = mv

I wasn't sure how to tackle this one, I made a few attempts but to no avail. Can anyone learn me up a bit.
 

Answers and Replies

  • #2
hage567
Homework Helper
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Look up the impulse-momentum theorem.
 
  • #3
14
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Thanks, that helped alot. I found the change in the x component of the momentum then divided by the time.
 
  • #4
hage567
Homework Helper
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That sounds good to me. :smile:
 

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