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## Main Question or Discussion Point

Consider this situation.

A non-rotating wheel is cruising through space such that its velocity vector is at some angle to the wheel plane. (Like when a car slides through ice when the driver turns the steering wheel). When its base touches a surface with friction, it takes a turn and its new velocity would point along the wheel plane. (assuming there's a mechanism that prevents it from toppling). This is because a frictional force in the direction opposite to the initial velocity acts on the wheel at the instant the wheel base touches the surface. It can be split into two components Fx and Fy(see images in the link) one along the wheel plane, one perpendicular to it at the point of contact with the surface. Fy completely destroys the momentum along the y direction while Fx rotates the wheel reducing the velocity till Vx=R*W(omega). So finally the wheel's velocity vector will be along Vx.

am i right in this explanation? Replies to this will take us forward to my doubt. :)

http://img25.imageshack.us/img25/892/dounbt.png [Broken]

A non-rotating wheel is cruising through space such that its velocity vector is at some angle to the wheel plane. (Like when a car slides through ice when the driver turns the steering wheel). When its base touches a surface with friction, it takes a turn and its new velocity would point along the wheel plane. (assuming there's a mechanism that prevents it from toppling). This is because a frictional force in the direction opposite to the initial velocity acts on the wheel at the instant the wheel base touches the surface. It can be split into two components Fx and Fy(see images in the link) one along the wheel plane, one perpendicular to it at the point of contact with the surface. Fy completely destroys the momentum along the y direction while Fx rotates the wheel reducing the velocity till Vx=R*W(omega). So finally the wheel's velocity vector will be along Vx.

am i right in this explanation? Replies to this will take us forward to my doubt. :)

http://img25.imageshack.us/img25/892/dounbt.png [Broken]

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