- #1

Rectifier

Gold Member

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**The problem**

I want to calculate ## \int^6_{-6} \frac{g(x)}{2+g(x)} \ dx ## for the step function below.

**The attempt**

I started with rewriting the function as with the help of long-division

## \int^6_{-6} \frac{g(x)}{2+g(x)} \ dx = \int^6_{-6} 1 \ dx - 2\int^6_{-6} \frac{1}{g(x)+2} \ dx##

I know that ##\int^6_{-6} 1 \ dx = 12## but thats about it. I am not sure how I should continue.

And here is where I get stuck.

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