Suppose [tex] U(x) [/tex] is the step function and [tex] \delta(x) [/tex] is its derivative. Find [tex] \int^{6}_{-2}(x^{2}-8)\delta(x)\dx [/tex]. I know [tex] \delta(x) = 0 [/tex] for all [tex] x [/tex] except [tex] x = 0 [/tex]. So at [tex] x = 0 [/tex] [tex] v(x) = - 8 [/tex]. After this step, how do we get [tex] \int_{-2}^{2}(x^{2}-8)\delta(x)\dx +\int^{6}_{2}(x^{2}-8)\delta(x)\dx = -8 + 0 [/tex]. How do you get the limits of integration?(adsbygoogle = window.adsbygoogle || []).push({});

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# Homework Help: Step Function

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