- #1

- 118

- 0

could someone show me the steps on how to simplify log5/log125 to 1/3. I cant do it :grumpy:

- Thread starter Gughanath
- Start date

- #1

- 118

- 0

could someone show me the steps on how to simplify log5/log125 to 1/3. I cant do it :grumpy:

- #2

- 180

- 0

Which base?

- #3

- 118

- 0

10, sorry for not mentioning that.danne89 said:Which base?

- #4

- 13,006

- 554

It doesn't matter the base,as long it is the same...

Daniel.

Daniel.

- #5

- 118

- 0

yes, so how could I simplify it?

- #6

- 13,006

- 554

[itex] 125=5^{3} [/itex] and use one definitory property of the logarithm...

Daniel.

Daniel.

- #7

- 118

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hmmm....that comes to log5 to the power -2?

- #8

- 180

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Why don't just: log5 125 = 3 and log5 5 = 1 and then just replace log 5 / log 125 = 1 / 3 ??

- #9

- 13,006

- 554

[tex] \frac{\log a}{\log b}\neq \log\frac{a}{b} [/tex]

So pay attention to what u do.

Daniel.

- #10

- 508

- 1

log(125) = log(5^{3}) = 3log(5)

- #11

- 118

- 0

oh right. My bad. so log5/log125 = log5/log5^3 = log5/3log5, the log5's cancel, leaving 1/3. Thanx

- #12

- 180

- 0

And then cancel out the log(5)s, leaving 1/3?

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