- #1

Paradox

## Main Question or Discussion Point

I was wondering how Stirling's approximation

x! ~ sqrt(2[pi]x)x

was derived. Anyone know?

x! ~ sqrt(2[pi]x)x

^{x}e^{-x}was derived. Anyone know?

- Thread starter Paradox
- Start date

- #1

Paradox

I was wondering how Stirling's approximation

x! ~ sqrt(2[pi]x)x^{x}e^{-x}

was derived. Anyone know?

x! ~ sqrt(2[pi]x)x

was derived. Anyone know?

- #2

- 3

- 0

This article at Mathworld derives Stirling's approximation step by step.

- #3

Paradox

Thanks for the link, Jeff. It helped a lot

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