I was wondering how Stirling's approximation x! ~ sqrt(2[pi]x)xxe-x was derived. Anyone know?
Apr 23, 2003 #1 Paradox I was wondering how Stirling's approximation x! ~ sqrt(2[pi]x)xxe-x was derived. Anyone know?
Apr 23, 2003 #2 Big Jeff 3 0 This article at Mathworld derives Stirling's approximation step by step.