I have a Gaussian trial wavefunction for the ground 1s state of H atom:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\psi (r)[/tex]= A Exp[-c r^2],

whereAis the normalization constant andcis the variational parameter.

I'm trying to calculate the variational integral W(c) = < [tex]\psi (r)[/tex] |H| [tex]\psi (r)[/tex]>, whereHis the Hamiltonian for the H-atom.

My question is wouldn't the angular momentum term operator, [tex]L^2[/tex], in the Hamiltonian disappear since the trial wavefunction only depends onr?

(And by the way, how do I use all those mathematical typesettings on this board?)

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# STO-1G for H-atom

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